ProjectionMediumQuestion 260011
Question
The projection of a⃗ on b⃗ is:
- A(a⃗ · b⃗)/|b⃗|Correct
- B(a⃗ · b⃗)/|a⃗|
- C|a⃗ × b⃗|/|b⃗|
- Da⃗ · b⃗
Correct answer
(a⃗ · b⃗)/|b⃗|
Explanation
Projection of a⃗ onto b⃗ = |a⃗|cos θ = |a⃗|(a⃗·b⃗)/(|a⃗||b⃗|) = (a⃗·b⃗)/|b⃗|.