Voltage from ChargeMediumQuestion 31509
Question
A 4 μF capacitor carries 20 μC. Its terminal voltage is:
- A80 V
- B5 VCorrect
- C0.2 V
- D16 V
Correct answer
5 V
Explanation
V = Q/C = 20 μC / 4 μF = 5 V.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
V = Q/C = 20 μC / 4 μF = 5 V.