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Question 31517
JEE Physics · Hard

Capacitance: Dielectric Introduction MCQ

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Dielectric IntroductionHardQuestion 31517

Question

Inserting a dielectric material of dielectric constant K between fully charged isolated capacitor plates (Q constant) changes the potential difference by factor:
  1. A
    K
  2. B
    1/K
    Correct
  3. C
    K²
  4. D
    √K

Correct answer

1/K

Explanation

Capacitance becomes KC; with Q fixed, V = Q/C decreases to V/K. The dielectric reduces the field by aligning dipoles.

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