Voltage Division SeriesMediumQuestion 31528
Question
Two capacitors C₁ = 2 μF and C₂ = 4 μF are in series across 12 V. Voltage across C₁ is:
- A8 VCorrect
- B4 V
- C6 V
- D2 V
Correct answer
8 V
Explanation
In series, V₁/V₂ = C₂/C₁ = 4/2 = 2. So V₁ = (2/3)×12 = 8 V. Smaller capacitor gets larger voltage.