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Question 31537
JEE Physics · Hard

Capacitance: Potential at Junction MCQ

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Potential at JunctionHardQuestion 31537

Question

Two capacitors 3 μF and 6 μF in series are connected across 90 V. Potential at the common junction (taking negative plate at 0) is:
  1. A
    30 V
  2. B
    60 V
    Correct
  3. C
    45 V
  4. D
    90 V

Correct answer

60 V

Explanation

V₁ (across 3 μF) = (C₂/(C₁+C₂))×V = (6/9)×90 = 60 V. Larger capacitor gets smaller voltage, so the junction is at 60 V above the negative terminal.

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