Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Capacitance/
Question 31562
JEE Physics · Medium

Capacitance: Charge After Redistribution MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Charge After RedistributionMediumQuestion 31562

Question

A 2 μF capacitor charged to 200 V is connected in parallel with an uncharged 3 μF capacitor. Charge on 3 μF capacitor at equilibrium is:
  1. A
    240 μC
    Correct
  2. B
    160 μC
  3. C
    400 μC
  4. D
    120 μC

Correct answer

240 μC

Explanation

Initial Q = 400 μC. Final V = 400/5 = 80 V. Charge on 3 μF = 3×80 = 240 μC.

Review Capacitance notesStart timed chapter practice