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Question 31587
JEE Physics · Hard

Capacitance: Opposite Polarity Connection MCQ

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Opposite Polarity ConnectionHardQuestion 31587

Question

Capacitor A (4 μF, 300 V) and capacitor B (12 μF, 50 V) are connected positive plate of A to negative plate of B. Net charge:
  1. A
    1200 μC
  2. B
    600 μC
    Correct
  3. C
    1800 μC
  4. D
    0 μC

Correct answer

600 μC

Explanation

Q_A = 1200 μC, Q_B = 600 μC (opposing). Net charge = 1200 − 600 = 600 μC. Final V = 600/16 = 37.5 V.

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