JEE Physics · Hard

Capacitance: Charge Induced Across Plates MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Charge Induced Across PlatesHardQuestion 31593

Question

A conducting slab (not connected to anything) is placed between the plates of a charged capacitor. The electric field inside the slab is:
  1. A
    Same as before
  2. B
    Half the original
  3. C
    Zero
    Correct
  4. D
    Double the original

Correct answer

Zero

Explanation

Inside a conductor in electrostatic equilibrium, E = 0. The conductor's free charges redistribute to cancel the external field inside.