Inelastic — Energy LossMediumQuestion 30525
Question
Two equal masses m collide head-on (one at v, other at rest) perfectly inelastically. Percentage of KE lost:
- A25%
- B50%Correct
- C75%
- D100%
Correct answer
50%
Explanation
v_f = v/2. KE_before = ½mv². KE_after = ½(2m)(v/2)² = mv²/4. Loss = ½mv²−mv²/4 = mv²/4. % loss = (mv²/4)/(½mv²) × 100 = 50%.