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Question 30544
JEE Physics · Hard

Center of Mass, Momentum and Collision: Superball Bounce MCQ

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Superball BounceHardQuestion 30544

Question

A ball (e = 0.8) is dropped from 10 m. Height after first bounce:
  1. A
    8 m
  2. B
    6.4 m
    Correct
  3. C
    4 m
  4. D
    0.64 m

Correct answer

6.4 m

Explanation

Speed before impact: v₁ = √(2g×10). After: v₂ = e×v₁ = 0.8v₁. Height: h₂ = v₂²/(2g) = e²×10 = 0.64×10 = 6.4 m.

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