JEE Physics · Hard

Circular Motion: Vertical Circle — Rod MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Vertical Circle — RodHardQuestion 30637

Question

A ball on a rigid rod (length r) in a vertical circle. At the top, the rod exerts a thrust (push) when speed v_top satisfies:
  1. A
    v_top < √(gr)
    Correct
  2. B
    v_top > √(gr)
  3. C
    v_top = √(gr)
  4. D
    v_top = 0 only

Correct answer

v_top < √(gr)

Explanation

At top: mg − F_rod = mv²/r. F_rod = mg − mv²/r. Rod pushes (thrust, positive outward) when F_rod < 0: v² < gr. Wait: if we define F_rod as pulling inward when positive: T = mv²/r − mg. When T < 0, rod pushes → v_top < √(gr).