JEE Physics · Hard

Circular Motion: Vertical Circle — Track MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Vertical Circle — TrackHardQuestion 30651

Question

A ball rolls in a vertical circular track (smooth) of radius r. At the top, the normal force from the track is N_top = mv²_top/r − mg. If the ball just completes the loop, N_top = 0 and:
  1. A
    v_top = 0
  2. B
    v_top = √(gr)
    Correct
  3. C
    v_top = √(2gr)
  4. D
    v_top = √(5gr)

Correct answer

v_top = √(gr)

Explanation

At the top of the track: gravity alone provides centripetal force → mg = mv²/r → v_top = √(gr). Same as for the string case.