Advanced — Variable Speed CircleHardQuestion 30669
Question
A particle moves in a circle with tangential acceleration a_t. The angle at which the resultant acceleration makes with the radius (centripetal direction) is:
- Aarctan(a_t/a_c)Correct
- Barctan(a_c/a_t)
- Carcsin(a_t/a_total)
- D45° always
Correct answer
arctan(a_t/a_c)
Explanation
a_c is radial (inward), a_t is tangential. The angle from the radial direction is φ where tanφ = a_t/a_c.