JEE Physics · Hard

Circular Motion: Advanced — Gravity Turn MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Advanced — Gravity TurnHardQuestion 30679

Question

At the equator, what angular velocity would make g_eff = 0 (objects become weightless)? (g = 9.8 m/s², R_Earth = 6.4×10⁶ m)
  1. A
    1.24×10⁻³ rad/s
    Correct
  2. B
    7.27×10⁻⁵ rad/s
  3. C
    0.00124 rad/s
  4. D
    0.0124 rad/s

Correct answer

1.24×10⁻³ rad/s

Explanation

g_eff = 0: g = ω²R → ω = √(g/R) = √(9.8/6.4×10⁶) = √(1.53×10⁻⁶) ≈ 1.24×10⁻³ rad/s. Compare with Earth's actual ω = 7.27×10⁻⁵ rad/s — Earth would need to spin ~17× faster!