Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Current Electricity/
Question 31612
JEE Physics · Medium

Current Electricity: Series Resistance MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Series ResistanceMediumQuestion 31612

Question

Three resistors 2 Ω, 3 Ω, 5 Ω in series. Total resistance is:
  1. A
    10 Ω
    Correct
  2. B
    0.97 Ω
  3. C
    30 Ω
  4. D
    1 Ω

Correct answer

10 Ω

Explanation

In series: R_total = R₁ + R₂ + R₃ = 2+3+5 = 10 Ω.

Review Current Electricity notesStart timed chapter practice