Current DensityHardQuestion 31616
Question
Current density J in a conductor is related to electric field E by:
- AJ = E/ρCorrect
- BJ = ρE
- CJ = ρ/E
- DJ = E²/ρ
Correct answer
J = E/ρ
Explanation
J = σE = E/ρ where σ is conductivity (σ = 1/ρ). This is the microscopic form of Ohm's law.