Kirchhoff ApplicationMediumQuestion 31629
Question
In a simple loop with EMF = 6 V, internal resistance 1 Ω, external resistance 2 Ω: current is:
- A2 ACorrect
- B6 A
- C3 A
- D1 A
Correct answer
2 A
Explanation
I = E/(R+r) = 6/(2+1) = 2 A.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
I = E/(R+r) = 6/(2+1) = 2 A.