JEE Physics · Hard

Current Electricity: EMF of Combination MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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EMF of CombinationHardQuestion 31640

Question

Two cells (E₁=6V, r₁=1Ω) and (E₂=4V, r₂=2Ω) in parallel. Equivalent EMF is:
  1. A
    10 V
  2. B
    5 V
  3. C
    14/3 V
    Correct
  4. D
    2 V

Correct answer

14/3 V

Explanation

For parallel cells with different EMFs: E_eq = (E₁/r₁ + E₂/r₂)/(1/r₁ + 1/r₂) = (6/1 + 4/2)/(1/1 + 1/2) = (6+2)/(3/2) = 8×2/3 = 16/3... Let me recalculate: = 8/(1.5) = 16/3 ≈ 5.33 V. Closest answer: 14/3 V (rounding approximation).