JEE Physics · Hard

Current Electricity: EMF of Combination MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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EMF of CombinationHardQuestion 31640

Question

Two cells (E₁=6V, r₁=1Ω) and (E₂=4V, r₂=2Ω) are connected in parallel with the same polarity. Their equivalent EMF is:
  1. A
    16/3 V
    Correct
  2. B
    10 V
  3. C
    5 V
  4. D
    14/3 V

Correct answer

16/3 V

Explanation

Eeq=(E1/r1+E2/r2)/(1/r1+1/r2)=(6+2)/(1+1/2)=<strong>16/3 V</strong>E_{eq}=(E_1/r_1+E_2/r_2)/(1/r_1+1/r_2)=(6+2)/(1+1/2)=<strong>16/3\text{ V}</strong>.