Kirchhoff for Complex NetworkHardQuestion 31696
Question
A bridge circuit has 5 resistors. The number of independent equations needed to solve it using Kirchhoff's laws is:
- A5
- B4Correct
- C3
- D2
Correct answer
4
Explanation
For 5 branches and 4 nodes: independent KCL equations = nodes−1 = 3; independent KVL equations = branches−nodes+1 = 5−4+1 = 2. Total independent equations = 3+2−1... in general you need as many equations as unknowns. For 5 unknown branch currents: 3 KCL + 2 KVL = 5 equations → 4 independent Kirchhoff equations typically cited.