Specific HeatMediumQuestion 30845
Question
200 g of water at 80°C is mixed with 200 g at 20°C. Final temperature is:
- A40°C
- B50°CCorrect
- C60°C
- D30°C
Correct answer
50°C
Explanation
Equal masses, same specific heat: T = (80 + 20)/2 = 50°C.
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
Equal masses, same specific heat: T = (80 + 20)/2 = 50°C.