JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Water Equivalent MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Water EquivalentHardQuestion 30854

Question

A 100 g calorimeter (c = 420 J/kg·K) contains 200 g water at 25°C. A hot metal sample (50 g, 100°C) is added and the final temperature is 29°C. The metal's specific heat is approximately:
  1. A
    994 J/kg·K
    Correct
  2. B
    400 J/kg·K
  3. C
    500 J/kg·K
  4. D
    600 J/kg·K

Correct answer

994 J/kg·K

Explanation

The calorimeter and water gain (0.1×420+0.2×4200)×4=3528(0.1×420+0.2×4200)×4=3528 J. The metal loses 0.05c(100−29)=3.55c0.05c(100-29)=3.55c J, so c=3528/3.55≈<strong>994 J/kg⋅K</strong>c=3528/3.55≈<strong>994\text{ J/kg·K}</strong>.