JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Calorimetry Principle MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Calorimetry PrincipleHardQuestion 30856

Question

Equal masses of aluminium (c = 900 J/kg·K) and iron (c = 450 J/kg·K) at 90°C and 30°C are mixed. Final temperature is:
  1. A
    50°C
  2. B
    60°C
  3. C
    70°C
    Correct
  4. D
    80°C

Correct answer

70°C

Explanation

Heat lost by Al = m×900×(90−T). Heat gained by Fe = m×450×(T−30). 900(90−T) = 450(T−30) → 2(90−T) = T−30 → 180−2T = T−30 → T = 70°C.