ConductionEasyQuestion 30862
Question
Thermal conductivity k has SI unit:
- AW·m/K
- BW/(m·K)Correct
- CJ·m/K
- DW/K
Correct answer
W/(m·K)
Explanation
From Q/t = kA(ΔT/L), k = (Q/t) × L / (AΔT) → W·m/(m²·K) = W/(m·K).
Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.
From Q/t = kA(ΔT/L), k = (Q/t) × L / (AΔT) → W·m/(m²·K) = W/(m·K).