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Question 30871
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Radiation MCQ

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RadiationHardQuestion 30871

Question

Temperature of the sun is 6000 K. Peak wavelength of emission is (b = 2.9×10⁻³ m·K):
  1. A
    483 nm
    Correct
  2. B
    580 nm
  3. C
    290 nm
  4. D
    960 nm

Correct answer

483 nm

Explanation

λ_max = b/T = 2.9×10⁻³/6000 ≈ 4.83×10⁻⁷ m = 483 nm (visible yellow-green).

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