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Question 30878
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Newton's Cooling MCQ

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Newton's CoolingHardQuestion 30878

Question

Using Newton's law of cooling, if average temperature of cooling is T_avg and surroundings is T₀, cooling rate dT/dt is approximately:
  1. A
    −k(T_avg + T₀)
  2. B
    −k(T_avg − T₀)
    Correct
  3. C
    −kT_avg
  4. D
    −kT₀

Correct answer

−k(T_avg − T₀)

Explanation

Approximate Newton's law: ΔT/Δt ≈ −k(T_avg − T₀) where T_avg = (T₁+T₂)/2.

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