JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Radiation Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Radiation AdvancedHardQuestion 30885

Question

A black body cools from temperature T to T/2. Ratio of rates of cooling at these temperatures is:
  1. A
    2:1
  2. B
    4:1
  3. C
    8:1
  4. D
    16:1
    Correct

Correct answer

16:1

Explanation

Rate of cooling ∝ T⁴ − T_sur⁴. If T_sur ≈ 0, rate ∝ T⁴. Ratio = T⁴/(T/2)⁴ = 16.