Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Elasticity, Thermal Expansion, Calorimetry and Heat Transfer/
Question 30888
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Elasticity Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Elasticity AdvancedHardQuestion 30888

Question

Two identical wires A and B are at same temperature. A is made of steel, B of copper (Y_steel > Y_copper). Same force applied. Which has greater strain?
  1. A
    A
  2. B
    B
    Correct
  3. C
    Both equal
  4. D
    Depends on length

Correct answer

B

Explanation

Strain = Stress/Y. Same stress, Y_steel > Y_copper → strain in B (copper) is greater.

Review Elasticity, Thermal Expansion, Calorimetry and Heat Transfer notesStart timed chapter practice