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Question 30893
JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Calorimetry Advanced MCQ

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Calorimetry AdvancedHardQuestion 30893

Question

A 100 W heater is switched on inside a thermally insulated room (heat capacity 8400 J/K). After 14 minutes, temperature rise is:
  1. A
    5°C
  2. B
    10°C
    Correct
  3. C
    15°C
  4. D
    20°C

Correct answer

10°C

Explanation

Energy = 100 × 14 × 60 = 84000 J. ΔT = Q/C = 84000/8400 = 10°C.

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