JEE Physics · Hard

Elasticity, Thermal Expansion, Calorimetry and Heat Transfer: Elasticity Advanced MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Elasticity AdvancedHardQuestion 30895

Question

A rubber cord of natural length L, cross-section A, elastic modulus E, is stretched to length 2L. Elastic potential energy stored is:
  1. A
    EAL/2
    Correct
  2. B
    EAL
  3. C
    2EAL
  4. D
    EAL/4

Correct answer

EAL/2

Explanation

Extension ΔL = L, strain = 1. Energy = ½ × stress × strain × volume = ½ × (E×1) × 1 × (AL) = EAL/2.