JEE Physics · Hard

Electromagnetic Induction and Alternating Current: Back EMF Calculation MCQ

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Back EMF CalculationHardQuestion 20230

Question

A DC motor draws 10 A from a 200 V supply. Its armature resistance is 2 Ω. Back EMF is:
  1. A
    180 V
    Correct
  2. B
    220 V
  3. C
    200 V
  4. D
    20 V

Correct answer

180 V

Explanation

Back EMF ε = V − IR = 200 − 10×2 = 180 V. The motor converts 180V×10A = 1800 W to mechanical power, while 10²×2 = 200 W is lost as heat in the armature.