Electromagnetic Induction — Self InductanceMediumQuestion 20249
Question
Self-inductance of a coil is 2 H. Current changes from 2 A to 6 A in 0.1 s. Induced back EMF is:
- A80 VCorrect
- B8 V
- C40 V
- D4 V
Correct answer
80 V
Explanation
|EMF| = L|dI/dt| = 2 × (6−2)/0.1 = 2 × 40 = 80 V.