Single-Slit Width and Minima CountHardQuestion 20229
Question
A single slit of width 0.2 mm is illuminated by λ = 500 nm. Angle of first diffraction minimum is:
- A0.25 mrad
- B2.5 mradCorrect
- C25 mrad
- D0.025 mrad
Correct answer
2.5 mrad
Explanation
a sinθ = λ → sinθ = λ/a = 500×10⁻⁹/0.2×10⁻³ = 2.5×10⁻³. For small angles sinθ ≈ θ = 2.5 mrad.