Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Electromagnetic Waves and Wave Optics/
Question 20247
JEE Physics · Easy

Electromagnetic Waves and Wave Optics: EM Spectrum Identification MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
EM Spectrum IdentificationEasyQuestion 20247

Question

A wave of frequency 3×10¹⁴ Hz belongs to which part of the EM spectrum?
  1. A
    Radio waves
  2. B
    Infrared
  3. C
    Visible light (red)
    Correct
  4. D
    X-rays

Correct answer

Visible light (red)

Explanation

λ = c/f = 3×10⁸/3×10¹⁴ = 10⁻⁶ m = 1000 nm. This is at the boundary of infrared and red visible light — approximately the near-IR/red region.

Review Electromagnetic Waves and Wave Optics notesStart timed chapter practice