Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Electrostatics/
Question 31424
JEE Physics · Medium

Electrostatics: Gauss's Law MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Gauss's LawMediumQuestion 31424

Question

By Gauss's law, field just outside a conductor surface with surface charge density σ is:
  1. A
    σ/ε₀
    Correct
  2. B
    σ/(2ε₀)
  3. C
    2σ/ε₀
  4. D
    ε₀/σ

Correct answer

σ/ε₀

Explanation

Using Gauss's law with a pillbox: E_out = σ/ε₀ (perpendicular to surface). Inside conductor: E = 0. The surface charge creates field σ/ε₀ outside.

Review Electrostatics notesStart timed chapter practice