Gauss's LawHardQuestion 31440
Question
Differential form of Gauss's law is:
- A∇·E = ρ
- B∇·E = ρ/ε₀Correct
- C∇×E = ρ/ε₀
- D∇²E = ρ/ε₀
Correct answer
∇·E = ρ/ε₀
Explanation
Maxwell's first equation: ∇·E = ρ/ε₀ where ρ is the free charge volume density. This is the differential (local) form of Gauss's law.