JEE Physics · Hard

Electrostatics: Electric Field MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Electric FieldHardQuestion 31470

Question

Electric field on axis of uniformly charged ring (charge Q, radius R) at distance x from centre:
  1. A
    kQx/(R²+x²)
  2. B
    kQx/(R²+x²)^(3/2)
    Correct
  3. C
    kQ/(R²+x²)
  4. D
    kQR/(R²+x²)^(3/2)

Correct answer

kQx/(R²+x²)^(3/2)

Explanation

E_axial = kQx/(R²+x²)^(3/2). Maximum at x = R/√2. Integrating ring elements, components perpendicular to axis cancel by symmetry.