Home/
Competitive Exams/
JEE Main & Advanced/
Physics/
Electrostatics/
Question 31473
JEE Physics · Hard

Electrostatics: Electric Field MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Electric FieldHardQuestion 31473

Question

Non-conducting sphere (radius R, uniform volume charge density ρ): ratio of fields at r = R/2 and r = 2R:
  1. A
    1:4
  2. B
    1:2
    Correct
  3. C
    2:1
  4. D
    1:1

Correct answer

1:2

Explanation

Inside (r=R/2): E_in = ρr/(3ε₀) = ρR/(6ε₀). Outside (r=2R): E_out = kQ/(2R)² = ρR³/(3ε₀×4R²) = ρR/(12ε₀). Ratio = (ρR/6ε₀)/(ρR/12ε₀) = 2:1. Hmm: E_in:E_out = 2:1. So answer is 2:1.

Review Electrostatics notesStart timed chapter practice