Mean Absolute ErrorMediumQuestion 30117
Question
Using the readings above (2.50, 2.53, 2.47, 2.51, 2.49 cm; mean = 2.50 cm), the mean absolute error is:
- A0.02 cmCorrect
- B0.03 cm
- C0.01 cm
- D0.04 cm
Correct answer
0.02 cm
Explanation
Deviations: 0.00, 0.03, 0.03, 0.01, 0.01. Mean absolute error = (0+0.03+0.03+0.01+0.01)/5 = 0.08/5 = 0.016 ≈ 0.02 cm.