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Question 30120
JEE Physics · Hard

Errors and Measurements: Error Combination MCQ

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Error CombinationHardQuestion 30120

Question

The period T of a pendulum is measured as T = (2.00 ± 0.02) s. If g is calculated as g = 4π²L/T², and %error in L is 1%, the %error in g is:
  1. A
    1%
  2. B
    2%
  3. C
    3%
    Correct
  4. D
    5%

Correct answer

3%

Explanation

%error in g = %error in L + 2×(%error in T) = 1 + 2×1 = 3%.

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