Pendulum g calculationMediumQuestion 30142
Question
In an experiment, L = 1.000 ± 0.001 m and T = 2.00 ± 0.01 s. The percentage error in g = 4π²L/T² is:
- A0.1% + 0.5%
- B0.1% + 1.0%Correct
- C1.0% + 1.0%
- D0.5% + 1.0%
Correct answer
0.1% + 1.0%
Explanation
%error in g = %error in L + 2×(%error in T) = (0.001/1.000)×100 + 2×(0.01/2.00)×100 = 0.1% + 1.0% = 1.1%.