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Question 30169
JEE Physics · Hard

Errors and Measurements: Propagation — JEE MCQ

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Propagation — JEEHardQuestion 30169

Question

Surface area of a sphere is S = 4πR². If %error in radius R is 1.5%, the %error in S is:
  1. A
    1.5%
  2. B
    3.0%
    Correct
  3. C
    6.0%
  4. D
    0.75%

Correct answer

3.0%

Explanation

S ∝ R². %error in S = 2 × %error in R = 2 × 1.5 = 3.0%.

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