JEE Physics · Hard

Errors and Measurements: Vernier Reading — Hard MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

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Vernier Reading — HardHardQuestion 30176

Question

A vernier (LC = 0.02 mm) has zero error −0.04 mm. If MSR = 12 mm and 8th VSD coincides, the corrected reading is:
  1. A
    12.20 mm
    Correct
  2. B
    12.16 mm
  3. C
    12.12 mm
  4. D
    12.24 mm

Correct answer

12.20 mm

Explanation

Observed = 12 + 8×0.02 = 12.16 mm. Negative zero error → correction = +0.04 mm. Corrected = 12.16 + 0.04 = 12.20 mm.