JEE Physics · Hard

Errors and Measurements: Screw Gauge — Thorough MCQ

Solve this quality-checked JEE multiple-choice question, then review the correct answer and explanation.

Timer-based practiceDetailed answer reviewMobile-friendly flow
Screw Gauge — ThoroughHardQuestion 30186

Question

A screw gauge has 0.5 mm pitch and 50 circular divisions (LC = 0.01 mm). Positive zero error = 0.03 mm. For a wire: MSR shows 1 complete division past 0, and CSR = 32. The correct diameter is:
  1. A
    0.82 mm
  2. B
    0.79 mm
    Correct
  3. C
    1.32 mm
  4. D
    1.29 mm

Correct answer

0.79 mm

Explanation

MSR: 1 division × 0.5 mm = 0.5 mm. CSR: 32 × 0.01 = 0.32 mm. Observed = 0.5 + 0.32 = 0.82 mm. Corrected = 0.82 − 0.03 = 0.79 mm.