Torricelli's TheoremMediumQuestion 30928
Question
A tank has water to height H. A hole at height h from bottom: water shoots out horizontally and lands at horizontal distance from hole equal to:
- A√(hH)
- B2√(h(H−h))Correct
- C√(2gH)
- D2√(H−h)
Correct answer
2√(h(H−h))
Explanation
v = √(2g(H−h)) (Torricelli). Time to fall h: h = ½gt² → t = √(2h/g). Range = v×t = √(2g(H−h))×√(2h/g) = 2√(h(H−h)).