Escape VelocityEasyQuestion 30723
Question
Escape velocity from Earth's surface is:
- A√(gR)
- B√(2gR)Correct
- C2gR
- DgR/2
Correct answer
√(2gR)
Explanation
From energy conservation (KE + PE = 0 at infinity): ½mv_e² = GMm/R = mgR → v_e = √(2gR) ≈ 11.2 km/s.