Gravitation: g at Combined Height+Depth MCQ

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g at Combined Height+DepthHardQuestion 30741

Question

g at height h = R/2 above the surface versus g at depth d = R/2 below the surface. The ratio g_h/g_d is:

8/9

$g_h=g/(1+h/R)^2=4g/9$ and, for a uniform Earth, $g_d=g(1-d/R)=g/2$ . Therefore $g_h/g_d=(4/9)/(1/2)=<strong>8/9</strong>$ .