JEE — Gravitational Field of RingHardQuestion 30766
Question
A uniform ring (mass M, radius a) has gravitational field along its axis at distance x from centre:
- AGMx/(a²+x²)^(3/2)Correct
- BGM/(a²+x²)
- CGMx/(a²+x²)
- DGM/(a+x)²
Correct answer
GMx/(a²+x²)^(3/2)
Explanation
By integration, the field along the axis of a ring: g = GMx/(a²+x²)^(3/2). It is zero at centre (x=0) and maximises at x = a/√2.