SpeedsMediumQuestion 31007
Question
The correct order of molecular speeds in a gas is:
- Av_mp < v_avg < v_rmsCorrect
- Bv_rms < v_avg < v_mp
- Cv_avg < v_mp < v_rms
- Dv_mp < v_rms < v_avg
Correct answer
v_mp < v_avg < v_rms
Explanation
v_mp = √(2RT/M), v_avg = √(8RT/πM), v_rms = √(3RT/M). Numerically: 1 : 1.128 : 1.225. Always v_mp < v_avg < v_rms.