EntropyHardQuestion 31040
Question
When 100 g of ice melts at 0°C (latent heat = 336 J/g), entropy change of ice is:
- A123 J/KCorrect
- B336 J/K
- C0 J/K
- D−123 J/K
Correct answer
123 J/K
Explanation
ΔS = Q/T = (100 × 336)/273 ≈ 123 J/K. Temperature must be in Kelvin.