EntropyHardQuestion 31056
Question
For mixing of two ideal gases at same T and P, entropy change is:
- AZero (no T change)
- BPositive (entropy of mixing)Correct
- CNegative (ordering increases)
- DDepends on molar masses
Correct answer
Positive (entropy of mixing)
Explanation
Mixing increases disorder → entropy of mixing ΔS_mix = −nR(x₁lnx₁ + x₂lnx₂) > 0 where x₁, x₂ are mole fractions.